Crystal Reports Removing data at the right of a string

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Topic: Removing data at the right of a string

Author	Message
Naithan Newbie Joined: 12 Mar 2012 Online Status: Offline Posts: 4	Topic: Removing data at the right of a string Posted: 12 Mar 2012 at 10:29pm
	I want to remove the last 3 characters of a string which could be any length and either alpha or numeric. E.G. nhttest001 needs to be nhttest 123456010 needs to be 123456 Anyone got any ideas how to do this ? Thanks
	Naithan
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DBlank Moderator Joined: 19 Dec 2008 Online Status: Offline Posts: 9053	Posted: 13 Mar 2012 at 3:41am
	left(field,len(field)-3)
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Naithan Newbie Joined: 12 Mar 2012 Online Status: Offline Posts: 4	Posted: 13 Mar 2012 at 3:52am
	Thanks for the reply, I changed your formula as shown and it gives a "boolean is required here" error message. left({Part.Part_Prim_Desc},len({Part.Part_Prim_Desc})-3) Cant work out why this would be. Help would be appreciated as I'm fairly new to Crystal (2008)
	Naithan
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DBlank Moderator Joined: 19 Dec 2008 Online Status: Offline Posts: 9053	Posted: 13 Mar 2012 at 4:30am
	did you put this in the select expert? The select expert is only used to select rows based on a boolean evaluation. go to the field explorer, right click on formula fields, select new, enter a name, put the formula there save it drag and drop the formula onto the report
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Naithan Newbie Joined: 12 Mar 2012 Online Status: Offline Posts: 4	Posted: 13 Mar 2012 at 10:37pm
	Oh that works almost perfect, thanks. Only one issue to deal with is that it gives an error of "string length is less than 0 or not an integer". I presume this is because in some cases there is no data to apply the formula too. So what is the best way of dealing with that whilst keeping the formula active? Much thanks for your help Naithan
	Naithan
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DBlank Moderator Joined: 19 Dec 2008 Online Status: Offline Posts: 9053	Posted: 14 Mar 2012 at 3:55am
	depends on what you want to return if the string is less than 3 characters (or empty). This emaple returns the orginal string if len({Part.Part_Prim_Desc})<3 then {Part.Part_Prim_Desc} else left({Part.Part_Prim_Desc},len({Part.Part_Prim_Desc})-3)
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Naithan Newbie Joined: 12 Mar 2012 Online Status: Offline Posts: 4	Posted: 14 Mar 2012 at 4:05am
	That works great, Thanks very much for your help, Much appreciated Naithan
	Naithan
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