Technical Questions
 Crystal Reports Forum : Crystal Reports 9 through 2022 : Technical Questions
Message Icon Topic: Julian Date to DD/MM/YYYY Post Reply Post New Topic
Author Message
Querida
Newbie
Newbie
Avatar

Joined: 03 Jun 2007
Location: Belgium
Online Status: Offline
Posts: 4
Quote Querida Replybullet Topic: Julian Date to DD/MM/YYYY
    Posted: 06 Jun 2007 at 12:27am
Hi all,
 
Can anyone tell me how I can translate a Julian date to a regular DD/MM/YYYY date?
For example: date stored as 107.157 needs to be displayed as 06/06/2007.
 
Thanks in advance,
Querida
IP IP Logged
hilfy
Admin Group
Admin Group
Avatar

Joined: 20 Nov 2006
Online Status: Offline
Posts: 3702
Quote hilfy Replybullet Posted: 06 Jun 2007 at 8:37pm

There is a Julian Date user function library available on the Business Objects website - http://technicalsupport.businessobjects.com

Do a search for "ufljul.exe"
 
-Dell


Edited by hilfy - 06 Jun 2007 at 8:38pm
IP IP Logged
Querida
Newbie
Newbie
Avatar

Joined: 03 Jun 2007
Location: Belgium
Online Status: Offline
Posts: 4
Quote Querida Replybullet Posted: 07 Jun 2007 at 12:52am

Thanks for your replay.

Unfortunately the function you mentioned isn’t what I was looking for. It can be used to convert ‘real julian dates’ (starting from January 1, 4713 B.C) but not the mathematical julian dates which are stored in our database.

Is there another existing function which converts these dates or can someone let me know how to create a function since I'm going to need this quit often.

IP IP Logged
BrianBischof
Admin Group
Admin Group
Avatar

Joined: 09 Nov 2006
Online Status: Offline
Posts: 2458
Quote BrianBischof Replybullet Posted: 07 Jun 2007 at 11:36am
I don't get it. Your julian dates are different from the standard julian dates? That sounds strange. Secondly, if your julian dates are unique to your company, then it would be tough for someone here to tell you how convert them. I found a thread on ExpertsExchange.com about this but you have to be a member to read the answers. So I copied a couple replies here. I have no idea if this will help you, but it should get you in the right direction.
==============================
This is a really easy formula to write, but I need to know the year for the sample dates you posted.
The number you posted first, is the number of days from a given date.  I need to determine that date to be able to supply you the formula.
So, can you give me the years for the sample date and expected outcome that you supplied?

Number    Expected Outcome
58829      Jan 24
57607      sept 20
58178      apr 14
58034      nov 21

The month and day are useless without the year.
If I get the year, we can then subtract the number of days to get the starting date.
The formula in Crystal would then look like this if the starting date was 1/1/1900

dateadd("d",{table.field},date(1900,1,1)
)
========================
Using dateadd("d",{table.field},date(1899,12,3
1)) yields the correct dates but the year is needed.

If you know the year for each date then you can use

dateadd("d",-{table.field},date(YEAR,1,24)) to determine the start point
Please support the forum! Tell others by linking to it on your blog or website:<a href="http://www.crystalreportsbook.com/forum/">Crystal Reports Forum</a>
IP IP Logged
Querida
Newbie
Newbie
Avatar

Joined: 03 Jun 2007
Location: Belgium
Online Status: Offline
Posts: 4
Quote Querida Replybullet Posted: 07 Jun 2007 at 11:44pm
Sorry if I didn't explain these julian days properly.
I'll try to explain these julian dates with the example I gave in the beginning.
107.157 is June 6 2007
1 --> the century = 20
07 --> the year = 07
157 --> the day = June 6
 
IP IP Logged
BrianBischof
Admin Group
Admin Group
Avatar

Joined: 09 Nov 2006
Online Status: Offline
Posts: 2458
Quote BrianBischof Replybullet Posted: 08 Jun 2007 at 12:13am
Alright. I decided to work on it before going to bed. Here is the formula I used to get this working. I convert it to a string and then parse out the parts of each date and convert them to numbers. Then I use the Date and AddDate functions to combine it into a normal date field.
numbervar JulianDate:=107.157;
stringvar DateString;
dateTimevar NewDate;
DateString := ToText(JulianDate,3);
NewDate:=Date (2000+ToNumber(Mid(DateString,2,2)),1 ,1 );
NewDate:=DateAdd("d", ToNumber(Mid(DateString,5, Length(DateString)-4))-1, NewDate);

Please support the forum! Tell others by linking to it on your blog or website:<a href="http://www.crystalreportsbook.com/forum/">Crystal Reports Forum</a>
IP IP Logged
Post Reply Post New Topic
Printable version Printable version

Forum Jump
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot delete your posts in this forum
You cannot edit your posts in this forum
You cannot create polls in this forum
You cannot vote in polls in this forum



This page was generated in 0.047 seconds.