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achandana01
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Quote achandana01 Replybullet Topic: Dates for recurring report
    Posted: 01 Jul 2014 at 11:14am
Hi,

I am working on a report where I need to caputure all admitted patients on Friday @ 12:01am and discharged by Sunday @ 12:01am.

This report will be run on every Monday and it captures previous weekend data.I am not sure how to put it in select criteria so that the report can run on every Monday without changing dates.

Thanks,
chand
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kevlray
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Quote kevlray Replybullet Posted: 01 Jul 2014 at 12:55pm
As long at the run time is consistent then you could always use an the dateadd function for the beginning and ending dates, something like this dateadd("d",{DateField}, -3) and dateadd("d",{DateField},-1). You should to concatenate the time in.  My brain just can't quite think how to do it at the moment.
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Gurbs
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Quote Gurbs Replybullet Posted: 01 Jul 2014 at 9:13pm
Can you describe the tables? Are both dates in the same table? And if not, how are they linked?
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achandana01
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Quote achandana01 Replybullet Posted: 02 Jul 2014 at 4:06am
@gurbs yes both dates are in the same table
chand
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achandana01
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Quote achandana01 Replybullet Posted: 02 Jul 2014 at 4:07am
@Kevlray

lets say the run time is not consistent for example I ran this report on Wednesday instead of Monday how could I still able to get data for friday thru sunday ?
chand
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kevlray
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Quote kevlray Replybullet Posted: 02 Jul 2014 at 5:44am
Nope.  In fact I goofed.  The only way it would work if I used a filter using the current date i.e.,  {Datefield} >= dateadd("d",currentdate, -3) and {Datefield} <= dateadd("d",currentdate,-2).  This should be a close approximation (I did not consider the time of day) and it would have to be run on Monday.  Do you have a way to schedule a report?  I hope this gets you in the right direction.
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DBlank
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Quote DBlank Replybullet Posted: 02 Jul 2014 at 7:36am
you might be able to simplify this to using the weekday value from your dataset
something like
datediff(day,admitdate,currendate)<5 and
datepart('w',admitdate) in [6,7,1] and
datediff(day,dischargedate,currendate)<5 and
datepart('w',dischargedate) in [6,7,1] and
 
 
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achandana01
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Quote achandana01 Replybullet Posted: 02 Jul 2014 at 10:02am
Thanks Dblank it worked for me :)
chand
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