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leedo
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Quote leedo Replybullet Topic: SUM conditional Field
    Posted: 02 Jul 2007 at 6:54am
Hi,

I am a bit lost here and need some help. I have the following fields in my report:

- Called Number<Text>
- Rate<Number>
- Duration <Number>
- Price<Formula> => Rate * Duration

Normally to simply sum the "Price" field I'd write: =>SUM({Cost_report.Calls})

However, I need to create two Summary fields. Each one only sums a subset of the the "Price" column based on a condition in the "CalledNumber" column as follows:

CalledNumber                   Price
------------------                   ------
97184323                          2.5
92343323                          23.00

84755543                          30.5
83343321                          8.0

94532234                          10.5
       

Sum for only numbers that begin with 9==> 36.00
Sum for only numbers that begin with 8==> 38.5

Any ideas?!!!Confused


Please used VB Syntax if possible.

Thanks






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jkwrpc
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Quote jkwrpc Replybullet Posted: 02 Jul 2007 at 9:28am
I have not tested this so the errors are mine,
---------------
If Mid (CStr({calledNumber},0)) = "8" then
formula = ({calledMinutes}* .385
else
formula =  ({calledMinutes}* .36)
-----------------------
 
What it trying to do is test the first digit of the number to see it is an 8.If it is then it is to calculate at one rate if it is not an 8 then it is to calculate at the other rate.
 
There are probably errors (the field names are wrong, but you should be able to sort them out easily enough.
 
Hope it helps.
 
Regards,
 
John W.
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leedo
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Quote leedo Replybullet Posted: 03 Jul 2007 at 6:47am
Thanks.. but I figured that I can use LEFT function to do it as well. I still need  to do the conditional summation in one formula field but aparently it cannot be done.
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jkwrpc
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Quote jkwrpc Replybullet Posted: 03 Jul 2007 at 2:04pm

If nothing else works,  you should be able to create a manual running total formula that would accept your conditions.  It would include similar logic to your LEFT, etc.

If you have not done this before, it is really quite simple. Let us know and me or someone else can help. 
 
It seems like you are close, so dont quit now.
 
 
Regards,
 
John W.
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leedo
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Quote leedo Replybullet Posted: 07 Jul 2007 at 3:16am
Thanks all for your help. I used the LEFT function and used the two running totals technique.

Thanks
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